89/VB02. problem / Math - Solved Math Problems

MR-89 / 87b. problem

Rationalize the denominator of the fraction:

$\frac{9}{\sqrt{12}}$

\frac{9}{\sqrt{12}}

= \frac{9}{\sqrt{12}} \cdot \frac{\sqrt{12}}{\sqrt{12}}

$= \frac{9 \sqrt{12}}{12}$

$= \frac{9 \sqrt{3 \cdot 4}}{12}$

= \frac{9 \sqrt{3} \cdot \sqrt{4}}{12}

= \frac{9 \sqrt{3} \cdot 2}{12}

$= \frac{3 \cdot 3 \sqrt{3} \cdot 2}{3 \cdot 4}$

$= \frac{3 \sqrt{3} \cdot 2}{4}$

$= \frac{3 \sqrt{3} \cdot 2}{2 \cdot 2}$

$= \frac{3 \sqrt{3}}{2}$

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