$$\frac{0,1^{-2}-{\left(0,4\right)}^0}{2{\displaystyle \frac{2}{3}}{\left({\displaystyle \frac{2}{3}}\right)}^{-3}+{\left(-{\displaystyle \frac{1}{3}}\right)}^{-1}}$$

$$=\frac{{\left({\displaystyle \frac{1}{10}}\right)}^{-2}-1}{{\displaystyle \frac{8}{3}}{\left({\displaystyle \frac{3}{2}}\right)}^3+{\left(-{\displaystyle \frac{3}{1}}\right)}^1}$$

$$=\frac{{\left({\displaystyle \frac{10}{1}}\right)}^2-1}{{\displaystyle \frac{\bcancel{8}}{\cancel{3}}}·{\displaystyle \frac{\cancel{27 }}{\bcancel{8}}}-{\displaystyle \frac{3}{1}}}$$

$$=\frac{{\displaystyle \frac{100}{1}}-1}{{\displaystyle \frac{1}{1}}·{\displaystyle \frac{9}{1}}-{\displaystyle \frac{3}{1}}}$$

$$=\frac{100-1}{{\displaystyle \frac{9}{1}}-{\displaystyle \frac{3}{1}}}$$

$$=\frac{99}{6}$$

$$=16\frac{3}{6}$$

$$=16\frac{1}{2}$$