MR-837 / 1200. problem

The volume of a regular eight-sided column 8 m3, and its height 2+1 m. Calculate the area of ​​the mantle.

B=8·a·h2

tg 22,5°=a2h

h=a2tg 22,5°=a2·tg 22,5°=a2·ctg 22,5°

ctg2 22,5°=1+cos 45°sin 45°

ctg2 22,5°=1+2222

ctg2 22,5°=2+2222

ctg2 22,5°=2+22 ·|22

ctg2 22,5°=2+2·22

ctg2 22,5°=22+22

ctg2 22,5°=22+12

ctg2 22,5°=2+1

h=a22+1

B=8·a·h2=8·a·a2·22+1

B=2a22+1

V=B·H=2a22+1·2+1

8=2a22+12

4=a22+12

a2=2+124

a=22+1

M=8·a·H

M=8·22+1·1+2

M=16