The volume of a regular eight-sided column 8 m3, and its height 2+1 m. Calculate the area of the mantle.
B=8·a·h2
tg 22,5°=a2h
h=a2tg 22,5°=a2·tg 22,5°=a2·ctg 22,5°
ctg2 22,5°=1+cos 45°sin 45°
ctg2 22,5°=1+2222
ctg2 22,5°=2+2222
ctg2 22,5°=2+22 ·|22
ctg2 22,5°=2+2·22
ctg2 22,5°=22+22
ctg2 22,5°=22+12
ctg2 22,5°=2+1
h=a22+1
B=8·a·h2=8·a·a2·22+1
B=2a22+1
V=B·H=2a22+1·2+1
8=2a22+12
4=a22+12
a2=2+124
a=22+1
M=8·a·H
M=8·22+1·1+2
M=16
ctg2 α=1+cos αsin α
V=B·H
M=16 m2