709/HK23. problem / Math - Solved Math Problems

MR-709 / 11. problem

Source: Magyarország: 2023 - Unified final exam for high schools - Mathematics - intermediate level [09.05.2023.] - 11..)

Geometry → Three-dimensional geometric shapes → Sphere

$V = \frac{4 π R^{3}}{3} = 1989$

$R^{3} = \frac{1989 \cdot 3}{4 \cdot π}$

$R = \sqrt[3]{\frac{1989 \cdot 3}{4 \cdot π}}$

$R \approx 7, 8$