Solve the equation below:
x2-2x-35=0
a=1; b=-2; c=-35;
x1,2=-b±b2-4ac2a
x1,2=--2±-22-4·1·-352·1
=2±4+1402
=2±1442
=2±122
x1=2+122
x1=142
x1=7
x2=2-122
x2=-102
x2=-5
Solution of a quadratic equation
a·x2+b·x+c=0
x2=7 ; x2=-5