MathReference -
Problems
MR-334 / 334. problem
Solve the following equation:
log
10
x
2
+
19
-
log
10
x
-
8
=
2
All Problems
Source:
MathReference: Generic Math Textbook - 334.)
Algebra → Exponential equations and inequalities → Exponential equations
log
10
x
2
+
19
-
log
10
x
-
8
=
2
log
10
x
2
+
19
-
log
10
x
-
8
=
2
log
10
x
2
+
19
-
log
10
x
-
8
=
l
o
g
10
10
2
l
o
g
10
x
2
+
19
-
l
o
g
10
x
-
8
=
log
10
100
l
o
g
10
x
2
+
19
x
-
8
=
log
10
100
x
2
+
19
x
-
8
=
100
x
2
+
19
=
100
x
-
8
x
2
+
19
=
100
x
-
800
x
2
+
19
-
100
x
+
800
=
0
x
2
-
100
x
+
819
=
0
x
1
,
2
=
100
-
10000
-
3276
2
x
1
,
2
=
100
±
6724
2
x
1
,
2
=
100
±
82
2
x
1
=
91
x
2
=
9
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