MR-249 / 249. problem

Determine the first derivative of the function below:

y=ln sin2x

y=ln sin2x

g=sin2x    y=ln g

u=sin x  ;  u'=cos x g=u2   g'=2·u·u'=2·sin x·cos x

y'=1g·g'

y'=1sin2x·2·sinx·cosx

y'=2cosxsinx

y'=2ctgx