180/VB01. problem / Math - Solved Math Problems

MR-180 / 825b. problem

Find the cube of the given expressions:

$x - 1$

${(x - 1)}^{3}$

$= x^{3} + 3 \cdot x^{2} \cdot (- 1) + 3 \cdot x \cdot {(- 1)}^{2} + {(- 1)}^{3}$

$= x^{3} - 3 x^{2} + 3 x - 1$

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