Solve the following equation:
x+2x-2+x-2x+2=0
x≠±2
x+22+x-22x-2x+2=0
x2+4x+4+x2-4x+4x-2x+2=0
x2+8x-2x+2=0
x=±-8
x=±8·-1
x=±4·2·i
x=±22i
x1=22i ; x2=-22i
ax2+bx+c=0 x1,2=-b±b2-4ac2a