MR-148 / 7. problem

Calculate the value of the following expression:

f(z)=-z3+3z2+z+2f(3+2i)

f(z)=-z3+3z2+z+2f(3+2i)=?

f(3+2i)

=-3+2i3+33+2i2+3+2i+2

=-27+3·32·2i+3·3·2i2+2i3+3·9+2·3·2i+2i2+3+2i+2

=-27+54i+9·4i2+8i3+3·9+12i+4i2+3+2i+2

=-27-54i-36-1-8-i+27+36i+12(-1)+3+2i+2

=+36-12+3+2+(-54+8+36+2)i

=29-8i

f(3+2i)=29-8i